有没有办法循环遍历json的所有键和值,从而通过匹配的路径或匹配的比较键或值确认和替换特定值,并在用key中的新值确认后同时在json之外创建新接口高朗
我看到的这个示例遍历所有值https://play.golang.org/p/xtiT2iGocBg,但是我不知道用匹配的路径或值替换值
最后!我完成了我所寻找的全部规格!!
https://play.golang.org/p/eN4-FjaQS97
package main import ( "encoding/json" "fmt" ) func main() { b := []byte(` { "iw":{"Ie":{"Itye":{"e":"eIe"}}}, "InnerJSON2":"NoneValue", "outterJSON":{ "innerJSON1":{ "value1":10, "value2":22 , "InnerInnerArray": [ "test1" , "test2"], "InnerInnerJSONArray": [ {"fld1" : "val1"} , {"fld2" : "val2"} ] }, "InnerJSON2":"NoneValue" } } `) f := map[string]interface{}{} if err := json.Unmarshal(b, &f); err != nil { panic(err) } verifyJSON(f) data, _ := json.MarshalIndent(f, "", " ") fmt.Println(string(data)) } func verifyJSON(bv interface{}) { var dumpJSON func(v interface{}, kn string) dumpJSON = func(v interface{}, kn string) { iterMap := func(x map[string]interface{}, root string) { var knf string if root == "root" { knf = "%v/%v" } else { knf = "%v/%v" } for k, v := range x { switch vv := v.(type) { case map[string]interface{}: fmt.Printf("%s => (map[string]interface{}) ...\n", fmt.Sprintf(knf, root, k)) case []interface{}: fmt.Printf("%s => ([]interface{}) ...\n", fmt.Sprintf(knf, root, k)) default: fmt.Printf("%s => %v\n", fmt.Sprintf(knf, root, k), vv) x[k] = "rgk" } dumpJSON(v, fmt.Sprintf(knf, root, k)) } } iterSlice := func(x []interface{}, root string) { var knf string if root == "root" { knf = "%v/%v" } else { knf = "%v/%v" } for k, v := range x { switch vv := v.(type) { case map[string]interface{}: fmt.Printf("%s => (map[string]interface{}) ...\n", fmt.Sprintf(knf, root, k)) case []interface{}: fmt.Printf("%s => ([]interface{}) ...\n", fmt.Sprintf(knf, root, k)) default: fmt.Printf("%s => %v\n", fmt.Sprintf(knf, root, k), vv) x[k] = "rg" } dumpJSON(v, fmt.Sprintf(knf, root, k)) } } switch vv := v.(type) { case map[string]interface{}: iterMap(vv, kn) case []interface{}: iterSlice(vv, kn) default: } } dumpJSON(bv, "root") }