我可以使用Golang将平面对象插入BigQuery中-如何将嵌套数据插入表中？

我的BigQuery模式如下所示（从示例中）：

[{
    "name": "kind",
    "mode": "nullable",
    "type": "string"
  },
  {
    "name": "fullName",
    "type": "string",
    "mode": "required"
  },
  { "name": "visit",
    "type": "record",
    "mode": "repeated",
    "fields": [
    {
       "name": "time",
       "type": "timestamp",
       "mode": "nullable"
    },
    {
       "name": "duration",
       "type": "integer",
       "mode": "nullable"
    }
   ]
  }
]

我的第一次插入尝试如下所示（示例）：

func ExampleInsert(f string,) {

  jsonRow := make(map[string]bigquery.JsonValue)

  bq, _ := bigquery.New(client)
  request := new(bigquery.TableDataInsertAllRequest)

  rows := make([]*bigquery.TableDataInsertAllRequestRows, 1)

  jsonRow["kind"] = bigquery.JsonValue(kind)
  jsonRow["visit_duration"] = bigquery.JsonValue(duration)

  rows[i] = new(bigquery.TableDataInsertAllRequestRows)
  rows[i].Json = jsonRow

  bq.Tabledata.InsertAll(projectID, "visits", "visitsv4", request)
  ...
}

哪个变平并插入没有问题。我只是在用visit_duration

但是，我需要遍历一个片段并添加到访问记录中。我试图建立一个 访问 对象（没有要测试的循环）并将其添加到行中，但它没有插入，并且我没有收到任何错误：

func ExampleInsert(f string,) {

  jsonRow := make(map[string]bigquery.JsonValue)

  bq, _ := bigquery.New(client)
  request := new(bigquery.TableDataInsertAllRequest)

  rows := make([]*bigquery.TableDataInsertAllRequestRows, 1)

  jsonRow["kind"] = bigquery.JsonValue(kind)

  visits := make([]*bigquery.TableDataInsertAllRequestRows, 1)

  jsonVisit := make(map[string]bigquery.JsonValue)
  jsonVisit["duration"] = rand.Intn(1000)
  visits[0] = new(bigquery.TableDataInsertAllRequestRows)
  visits[0].Json = jsonVisit

  jsonRow["visit"] = visits

  rows[i] = new(bigquery.TableDataInsertAllRequestRows)
  rows[i].Json = jsonRow

  bq.Tabledata.InsertAll(projectID, "visits", "visitsv4", request)

  _, err := Call.Do()
}

- -[解] - -

如评论中所建议，我还尝试创建一个切片，然后附加访问：

var visits []bigquery.JsonValue
visit := make(map[string]bigquery.JsonValue)
visit["duration"] = rand.Intn(100)
visits = append(visits, visit)

jsonRow["visit"] = visits

我可以确认这实际上是可行的：)对于那些阅读此书的人来说，即使添加了片后它最初也不是因为我已经复制了表。这样，我也将结果弄平了。小心。