我正在尝试跟Rob Pike的Google I / O 2012演讲“ Go Concurrency”一起进行。我正在尝试通道多路复用的示例，以使“
Ann”和“ Joe”不会步调一致。但是使用下面的代码，它们仍然处于锁定状态。我要去哪里错了？

视频：http
:
//www.youtube.com/watch?v=
f6kdp27TYZs&
feature=player_detailpage#
t=
1025s

package main

import (
    "fmt"
    "time"
    "math/rand"
    )

func fanIn(input1, input2 <-chan string) <-chan string {
    c := make(chan string)
    go func() { for {c <- <-input1 } }()
    go func() { for {c <- <-input2 } }()
    return c
}

func main() {
    c := fanIn(boring("Joe"), boring("Ann"))
    for i:=0; i<10; i++ {
        fmt.Println(<-c)
    }
    fmt.Printf("You're both boring, I'm leaving...\n")
}

func boring(msg string) <-chan string {
    c := make(chan string)
    go func() { // launch goroutine from inside the fn
        for i:=0; ; i++ {
            c <- fmt.Sprintf("%s %d", msg, i)
            time.Sleep(time.Duration(rand.Intn(1e3)) * time.Millisecond )
        }
    }()
    return c
}

以及它的输出（在Ubuntu 10.04 LTS上为go1.0.2版）

Joe 0
Ann 0
Joe 1
Ann 1
Joe 2
Ann 2
Joe 3
Ann 3
Joe 4
Ann 4
You're both boring, I'm leaving...

我哪里做错了？谢谢！