将所有数组成员拆分为新数组：具有完整component属性（不仅是数字）的成员和不具有完整属性的成员。循环遍历应该只具有数字component属性的其余原始成员，然后@componentID从“好”数组中查找对应的成员，并进行一些复制和移动。

// initialize some vars
var final = [], temp = [], bad = [],
    c = {},
    computers = [
      {
        "@computerID": 1,
        "component": {
          "@componentID": 2,
          "processor": 2,
          "ram": "8g",
          "harddrive": "wd"
        }
      },
      {
        "@computerID": 3,
        "component": 2
      }
    ];

// split original array into 3: final, bad, & temp
while(computers.length > 0) {
    c = computers.pop();
    if (c.hasOwnProperty("component")) {
        if (typeof c.component === "number") {
            temp.push(c);
        } else {
            final.push(c);
        }
    } else {
        bad.push(c);
    }
}

// loop through temp & look up @componentID within final
while (temp.length > 0) {
    c = temp.pop();
    // should @componentID be 1-of-a-kind?
    var found = getObjects(final, "@componentID", c.component);
    if (found.length) {
        c.component = found[0];
        final.push(c);
    } else {
        bad.push(c);
    }
}


// SOURCE: http://stackoverflow.com/a/4992429/1072176
function getObjects(obj, key, val) {
    var objects = [];
    for (var i in obj) {
        if (!obj.hasOwnProperty(i)) continue;
        if (typeof obj[i] == 'object') {
            objects = objects.concat(getObjects(obj[i], key, val));
        } else if (i == key && obj[key] == val) {
            objects.push(obj);
        }
    }
    return objects;
}

// should result in just one or two populated arrays: final and/or bad
alert(JSON.stringify(final));

您会注意到，我实际上制作了三个数组，但最后只填充了两个：final拥有好的新对象，而另一个（bad）是对没有组件属性的对象或组件编号为对应的@componentID的对象的统称找不到。