一尘不染

如何按顺序使用angularjs $ q链接promise?

angularjs

在promise库 Q中 ,您可以执行以下操作以顺序链接promise:

var items = ['one', 'two', 'three'];
var chain = Q();
items.forEach(function (el) {
  chain = chain.then(foo(el));
});
return chain;

但是,以下命令不适用于 $ q

var items = ['one', 'two', 'three'];
var chain = $q();
items.forEach(function (el) {
  chain = chain.then(foo(el));
});
return chain;

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2020-07-04

共1个答案

一尘不染

只需使用$ q.when()函数:

var items = ['one', 'two', 'three'];
var chain = $q.when();
items.forEach(function (el) {
  chain = chain.then(foo(el));
});
return chain;

注意:foo必须是工厂,例如

function setTimeoutPromise(ms) {
  var defer = $q.defer();
  setTimeout(defer.resolve, ms);
  return defer.promise;
}

function foo(item, ms) {
  return function() {
    return setTimeoutPromise(ms).then(function () {
      console.log(item);
    });
  };
}

var items = ['one', 'two', 'three'];
var chain = $q.when();
items.forEach(function (el, i) {
  chain = chain.then(foo(el, (items.length - i)*1000));
});
return chain;
2020-07-04