数组中的JSON对象数组在javascript中查找和替换

一尘不染

数组中的JSON对象数组在javascript中查找和替换

angularjs

我有一个像这样的JSON对象：

var myObject = [    
{
    "Name" : "app1",
    "id" : "1",
    "groups" : [
        { "id" : "test1", 
          "name" : "test group 1", 
          "desc" : "this is a test group"
         },
        { "id" : "test2",
          "name" : "test group 2",
          "desc" : "this is another test group"
         }
    ]
},
{
    "Name" : "app2",
    "id" : "2",
    "groups" : [
        { "id" : "test3", 
          "name" : "test group 4", 
          "desc" : "this is a test group"
         },
        { "id" : "test4",
          "name" : "test group 4",
          "desc" : "this is another test group"
         }
    ]
},
 {
    "Name" : "app3",
    "id" : "3",
    "groups" : [
        { "id" : "test5", 
          "name" : "test group 5", 
          "desc" : "this is a test group"
         },
        { "id" : "test6",
          "name" : "test group 6",
          "desc" : "this is another test group"
         }
    ]
}

];

我为特定的“ id”提供了“名称”的新值。如何在任何对象内替换特定“ id”的“名称”？

以及如何计算所有对象之间的组总数？

例如：将名称替换为“ test grp45”，ID =“ test1”

这是小提琴 http://jsfiddle.net/qLTB7/21/

阅读 762

2020-07-04

共1个答案

一尘不染

以下函数将搜索对象及其所有子对象/数组，并将键替换为新值。它会在全球范围内应用，因此在第一次替换后不会停止。取消注释注释行，以使其成为注释。

function findAndReplace(object, value, replacevalue) {
  for (var x in object) {
    if (object.hasOwnProperty(x)) {
      if (typeof object[x] == 'object') {
        findAndReplace(object[x], value, replacevalue);
      }
      if (object[x] == value) { 
        object["name"] = replacevalue;
        // break; // uncomment to stop after first replacement
      }
    }
  }
}

可用的jsfiddle：http :
//jsfiddle.net/qLTB7/28/

2020-07-04