如果您确实确实需要使用rowspans进行处理，这是一种处理方法，除非您是作者（对不起），否则它很难完成并且几乎不可能阅读/关注，但是可以使用。您只需要夫妇$filter的支持

像这样：

angular.module('testApp', [])
.controller('testController', function ($scope) {
    $scope.testData = {
        'Key 1': {
            'Value 1': ['a', 'b', 'c'],
            'Value 2': ['d', 'e']
        },
        'Key 2': {
            'Value 3': ['f'],
            'Value 4': ['g', 'h']
        }
    };
})
.filter('nNestedElements', function(){
    var nNestedElements = function(collection, currentLevel, stopLevel){
        var total = 0;
        if(stopLevel==currentLevel){
            if(Object.prototype.toString.call(collection) === '[object Array]')
                total += collection.length;
            else
                total += Object.keys(collection);
        }else{
            angular.forEach(collection, function(value){
                total += nNestedElements(value, currentLevel+1, stopLevel);                
            });
        }
        return total;
    };
    return function(object, level){                
        return nNestedElements(object, 0, level);
    }
})
.filter('objectKeys', function(){
    return function(object){
        return Object.keys(object);
    };
});

视图：

<table ng-app="testApp" ng-controller="testController">
    <tr ng-repeat-start="(key, val) in testData">
        <td rowspan="{{val|nNestedElements:1}}">{{key}}</td>
        <td rowspan="{{val[(val|objectKeys)[0]].length}}">{{(val|objectKeys)[0]}}</td>
        <td>{{ val[(val|objectKeys)[0]][0]}}</td>
    </tr>
    <tr ng-repeat="val2 in val[(val|objectKeys)[0]].slice(1)">
        <td>{{val2}}</td>
    </tr>
    <tr ng-repeat-start="subkey in (val|objectKeys).slice(1)">
        <td rowspan="{{val[subkey].length}}">{{subkey}}</td>
        <td>{{ val[subkey][0] }}</td>
    </tr>
    <tr ng-repeat="value3 in val[subkey].slice(1)" ng-repeat-end>        
        <td>{{ value3 }}</td>
    </tr>
    <tr ng-repeat-end ng-if="false" ><td></td></tr>
</table>

例