有没有办法在Swift中获取设备型号名称（iPhone 4S，iPhone 5，iPhone 5S等）？
我知道有一个名为的属性，UIDevice.currentDevice().model但它仅返回设备类型（iPod touch，iPhone，iPad，iPhone Simulator等）。
UIDevice.currentDevice().model
我也知道使用此方法可以轻松在Objective-C中完成：
#import <sys/utsname.h> struct utsname systemInfo; uname(&systemInfo); NSString* deviceModel = [NSString stringWithCString:systemInfo.machine encoding:NSUTF8StringEncoding];
但是我正在用Swift开发我的iPhone应用程序，所以有人可以帮我用等效的方法来解决这个问题吗？
我在上做了这个“ pure Swift”扩展UIDevice。
UIDevice
此版本适用于Swift 2或更高版本。 如果您使用的是较早版本，请使用我的答案的较旧版本。
如果您正在寻找更优雅的解决方案，则可以使用我DeviceKit在GitHub上发布的µ-framework（也可以通过CocoaPods，Carthage和Swift Package Manager获得）。
DeviceKit
这是代码：
import UIKit public extension UIDevice { static let modelName: String = { var systemInfo = utsname() uname(&systemInfo) let machineMirror = Mirror(reflecting: systemInfo.machine) let identifier = machineMirror.children.reduce("") { identifier, element in guard let value = element.value as? Int8, value != 0 else { return identifier } return identifier + String(UnicodeScalar(UInt8(value))) } func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity #if os(iOS) switch identifier { case "iPod5,1": return "iPod touch (5th generation)" case "iPod7,1": return "iPod touch (6th generation)" case "iPod9,1": return "iPod touch (7th generation)" case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4" case "iPhone4,1": return "iPhone 4s" case "iPhone5,1", "iPhone5,2": return "iPhone 5" case "iPhone5,3", "iPhone5,4": return "iPhone 5c" case "iPhone6,1", "iPhone6,2": return "iPhone 5s" case "iPhone7,2": return "iPhone 6" case "iPhone7,1": return "iPhone 6 Plus" case "iPhone8,1": return "iPhone 6s" case "iPhone8,2": return "iPhone 6s Plus" case "iPhone8,4": return "iPhone SE" case "iPhone9,1", "iPhone9,3": return "iPhone 7" case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus" case "iPhone10,1", "iPhone10,4": return "iPhone 8" case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus" case "iPhone10,3", "iPhone10,6": return "iPhone X" case "iPhone11,2": return "iPhone XS" case "iPhone11,4", "iPhone11,6": return "iPhone XS Max" case "iPhone11,8": return "iPhone XR" case "iPhone12,1": return "iPhone 11" case "iPhone12,3": return "iPhone 11 Pro" case "iPhone12,5": return "iPhone 11 Pro Max" case "iPhone12,8": return "iPhone SE (2nd generation)" case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2" case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad (3rd generation)" case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad (4th generation)" case "iPad6,11", "iPad6,12": return "iPad (5th generation)" case "iPad7,5", "iPad7,6": return "iPad (6th generation)" case "iPad7,11", "iPad7,12": return "iPad (7th generation)" case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air" case "iPad5,3", "iPad5,4": return "iPad Air 2" case "iPad11,4", "iPad11,5": return "iPad Air (3rd generation)" case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad mini" case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad mini 2" case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad mini 3" case "iPad5,1", "iPad5,2": return "iPad mini 4" case "iPad11,1", "iPad11,2": return "iPad mini (5th generation)" case "iPad6,3", "iPad6,4": return "iPad Pro (9.7-inch)" case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)" case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch) (1st generation)" case "iPad8,9", "iPad8,10": return "iPad Pro (11-inch) (2nd generation)" case "iPad6,7", "iPad6,8": return "iPad Pro (12.9-inch) (1st generation)" case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)" case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)" case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)" case "AppleTV5,3": return "Apple TV" case "AppleTV6,2": return "Apple TV 4K" case "AudioAccessory1,1": return "HomePod" case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))" default: return identifier } #elseif os(tvOS) switch identifier { case "AppleTV5,3": return "Apple TV 4" case "AppleTV6,2": return "Apple TV 4K" case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))" default: return identifier } #endif } return mapToDevice(identifier: identifier) }() }
您这样称呼它：
let modelName = UIDevice.modelName
对于真实设备，它返回例如“ iPad Pro 9.7英寸”，对于模拟器，它返回“模拟器” +模拟器标识符，例如“ Simulator iPad Pro 9.7英寸”
