如何在Swift语言中实现反射?
如何实例化课程
[[NSClassFromString(@"Foo") alloc] init];
请注意,Swift类现在已命名为名称空间,因此它将是“ AppName.MyViewController”而不是“ MyViewController”
从XCode6-beta 6/7开始不推荐使用 使用XCode6-beta 3开发的解决方案
从XCode6-beta 6/7开始不推荐使用
使用XCode6-beta 3开发的解决方案
多亏了Edwin Vermeer的回答,我能够通过执行以下操作来构建一些东西来将Swift类实例化为Obj-C类:
// swift file // extend the NSObject class extension NSObject { // create a static method to get a swift class for a string name class func swiftClassFromString(className: String) -> AnyClass! { // get the project name if var appName: String? = NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleName") as String? { // generate the full name of your class (take a look into your "YourProject-swift.h" file) let classStringName = "_TtC\(appName!.utf16count)\(appName)\(countElements(className))\(className)" // return the class! return NSClassFromString(classStringName) } return nil; } } // obj-c file #import "YourProject-Swift.h" - (void)aMethod { Class class = NSClassFromString(key); if (!class) class = [NSObject swiftClassFromString:(key)]; // do something with the class }
编辑
您也可以在纯obj-c中执行此操作:
- (Class)swiftClassFromString:(NSString *)className { NSString *appName = [[NSBundle mainBundle] objectForInfoDictionaryKey:@"CFBundleName"]; NSString *classStringName = [NSString stringWithFormat:@"_TtC%d%@%d%@", appName.length, appName, className.length, className]; return NSClassFromString(classStringName); }
我希望这会对某人有所帮助!