如何将CVPixelBufferGetBaseAddress调用转换为Swift？

一尘不染

如何将CVPixelBufferGetBaseAddress调用转换为Swift？

swift

也许我是Swift中第一个这样做的人，但在Swift中使用＆/ inout和uint8_t似乎在网上没有任何东西。有人可以翻译一下吗？这种关系是按位的吗？

目标C

uint8_t *buf=(uint8_t *) CVPixelBufferGetBaseAddress(cvimgRef);

快速尝试

let inout buf:uint8_t = SOMETHING HERE CVPixelBufferGetBaseAddress(cvimgRef)

阅读 513

2020-07-07

共1个答案

一尘不染

CVPixelBufferGetBaseAddress()返回一个UnsafeMutablePointer<Void>，可以通过将其转换为UInt8指针

let buf = UnsafeMutablePointer<UInt8>(CVPixelBufferGetBaseAddress(pixelBuffer))

Swift 3（Xcode 8）的更新，Swift 5（Xcode 11）的检查：

if let baseAddress = CVPixelBufferGetBaseAddress(pixelBuffer) {
    let buf = baseAddress.assumingMemoryBound(to: UInt8.self)
    // `buf` is `UnsafeMutablePointer<UInt8>`
} else {
    // `baseAddress` is `nil`
}

2020-07-07