假设我需要一个模块并执行以下操作:
var b = require('./b.js'); --- do something with b ---
然后,我要拿走模块b(即清理缓存)。我该怎么办?
原因是我想动态加载/删除或更新模块,而无需重新启动节点服务器。任何想法?
-------更多--------根据删除require.cache的建议,它仍然不起作用…
what I did are few things: 1) delete require.cache[require.resolve('./b.js')]; 2) loop for every require.cache's children and remove any child who is b.js 3) delete b
但是,当我呼叫b时,它仍然存在!它仍然可以访问。除非我这样做:
b = {};
不知道这是否是处理该问题的好方法。因为如果以后再修改b.js,我又需要(’./b.js’)。它需要旧的缓存b.js(我尝试删除)还是新的?
-----------更多发现--------------
好。我进行了更多的测试,并尝试了代码。.这是我发现的:
1) delete require.cache[] is essential. Only if it is deleted, then the next time I load a new b.js will take effect. 2) looping through require.cache[] and delete any entry in the children with the full filename of b.js doesn't take any effect. i.e. u can delete or leave it. However, I'm unsure if there is any side effect. I think it is a good idea to keep it clean and delete it if there is no performance impact. 3) of course, assign b={} doesn't really necessary, but i think it is useful to also keep it clean.
您可以使用此命令在缓存中删除其条目:
delete require.cache[require.resolve('./b.js')]
require.resolve()将找出的完整路径./b.js,该路径用作缓存键。
require.resolve()
./b.js