一尘不染

Perl脚本来解析需要身份验证的Jenkins作业(config.xml)文件

jenkins

我正在尝试解析Jenkins作业“ config.xml”文件。

这是我尝试使用 HTTP :: Tiny 的一种方法:

use HTTP::Tiny;

my $page = "http://localhost:8080/job/Job_One_Name/config.xml";
system("start $page");  # this loads the xml file in browser successfully

my $wsdlResponse = HTTP::Tiny->new->get($page);
$wsdlResponse->{success} or die print $logger->error_die($!); 
my $wsdlXML = XML::LibXML->new->parse_file($wsdlResponse->{content});

print $wsdlXML;

它死于错误 “错误的文件描述符”

如果我注释掉该行,则脚本在parse_file行处中断,并显示以下错误消息:

Could not create file parser context for file "<html><head><meta http-equiv='refresh' content='1;url=/login?from=%2Fjo
b%2FJob_One_Name/config.xml'/><script>window.location.replace('/login?from=%2Fjob%2FJob_One_Name/config.xml');</script></head><body style='background-color:white; color:white;'>

Authentication required                                                                                               
<!--                                                                                                                  
You are authenticated as: anonymous                                                                                   
Groups that you are in:

Permission you need to have (but didn't): hudson.model.Hudson.Read                                                    
 ... which is implied by: hudson.security.Permission.GenericRead                                                      
 ... which is implied by: hudson.model.Hudson.Administer                                                              
-->

</body></html>                                                                                                      
                ": Result too large at Job.pm line 67.

我也从不同的示例在线尝试了 XML :: TwigLibXML- > load_xmlload_html
,但是它们都死于类似于 “无法为文件创建文件解析器上下文”“错误的文件描述符”“指定 ”的错误。 位置,字符串或IO”

关于可能是什么的任何想法?提前致谢。

更新:

遵循詹金斯(Jenkins)的“ 身份验证脚本客户 端”中的“脚本客户端的Perl
LWP示例
” ,我已经成功地进行了身份验证:

my $uagent = LWP::UserAgent->new(cookie_jar => HTTP::Cookies->new());
my %options = {'myUserName' => 'myPassword'};
$req = HTTP::Request->new( GET => $serverHost );
$req->authorization_basic( 'myUserName', 'myPassword' );
my $res = $uagent->request($req);

# Check the outcome of the response
print "Result: " . $res->status_line . "\n";
print $res->headers->as_string;
print "\n";
if ( !$res->is_success ) {
    print "Failed\n";
} else {
    print "Success!\n";

    # Parse XML
    my $wsdlResponse = HTTP::Tiny->new->get($page, \%options);
    #$dom = XML::LibXML->load_xml(location=>$page);     
    #print $dom . "\n";
    my $wsdlXML = XML::LibXML->new->parse_file($wsdlResponse->{content});
    print $wsdlXML;
    #print $res->content, "\n";
}

它仍然给我同样的 “需要身份验证” 错误。我不知道如何使用成功的授权请求来解析文件。


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2020-07-25

共1个答案

一尘不染

我想出了一种使用经过身份验证的请求输出结果的方法。由于请求输出xml内容以及标头响应,即:

HTTP/1.1 200 OK
Connection: close
Server: Jetty(8.y.z-SNAPSHOT)
Content-Type: application/xml
Client-Date: Wed, 30 Jul 2014 14:49:12 GMT
Client-Peer: 127.0.0.1:8080
Client-Response-Num: 1

<?xml version... 
<project>
  ....
  ....
</project>

我使用正则表达式 提取输出的xml部分并将其保存到文件中。从那里,我使用LibXML的 parse_file
方法来解析新写入的文件。(我有一个单独的子例程,该例程使用 findnodes
方法提取我想提取的特定节点。由于该解决方案处理了我遇到的身份验证问题,所以我没有发布它)。

解:

use strict;
use warnings;
use XML::LibXML;
use Path::Class;
use LWP;
use HTTP::Cookies;

my $serverXmlUrl = "http\://localhost:8080/job/jobName/config.xml";
my $uagent = LWP::UserAgent->new(cookie_jar => HTTP::Cookies->new());
my $request = HTTP::Request->new( GET => $serverXmlUrl );
$request->authorization_basic( 'UserName', 'Password' );
my $result = $uagent->request($request);

if ( !$result->is_success ) {
    print "Failed\n";
} else {
    print "Success!\n";

    # Create new file to write to
    my $dir         = dir(".");
    my $file        = $dir->file("job.xml");
    my $file_handle = $file->openw();
    my $xml_content = $result->as_string; # full result output

    # Regex to store only xml content
    $xml_content =~ s/.*(<\?xml.*)/$1/s; 
    # Save xml_content to file
    $file_handle->print($xml_content);
    $file_handle->close();
    # Parse newly written file
    print "Parsing file... \n";
    my $parser = XML::LibXML->new();
    my $doc    = $parser->parse_file($file);
    print $doc;
}
2020-07-25