一尘不染

获取单选按钮值并通过Ajax发送到php

ajax

我在我的网站上进行了一项民意调查,该调查在每个答案旁边都显示了单选按钮。当用户选择一个选项并提交时,我通过ajax运行php脚本,以将值或选定的单选按钮插入表中。

我的Ajax正在运行,但当前每行插入一个0行,因此它没有从单选按钮中获取值。任何帮助,将不胜感激。

HTML:

<form id="poll_form" method="post" accept-charset="utf-8">  
    <input type="radio" name="poll_option" value="1" id="poll_option" /><label for='1'>&nbsp;Arts</label><br />
    <input type="radio" name="poll_option" value="2" id="poll_option" /><label for='2'>&nbsp;Film</label><br />
    <input type="radio" name="poll_option" value="3" id="poll_option" /><label for='3'>&nbsp;Games</label><br />
    <input type="radio" name="poll_option" value="4" id="poll_option" /><label for='4'>&nbsp;Music</label><br />
    <input type="radio" name="poll_option" value="5" id="poll_option" /><label for='5'>&nbsp;Sports</label><br />
    <input type="radio" name="poll_option" value="6" id="poll_option" /><label for='6'>&nbsp;Television</label><br />    
    <input type="submit" value="Vote &rarr;" id="submit_vote" class="poll_btn"/> 
</form>

AJAX:

    $("#submit_vote").click(function(e)
    { 
    var option=$('input[type="radio"]:checked').val();
    $optionID = "="+optionID;

    $.ajax({
        type: "POST",
        url: "ajax_submit_vote.php",
        data: {"optionID" : $optionID}
    });
});

PHP :(简化版)

    if($_SERVER['REQUEST_METHOD'] == "POST"){

    //Get value from posted form
    $option = $_POST['poll_option'];

    //Insert into db
    $insert_vote = "INSERT into poll (userip,categoryid) VALUES ('$ip','$option')";

提前致谢!


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2020-07-26

共1个答案

一尘不染

$("#submit_vote").click(function(e){

    $.ajax( {
      type: "POST",
      url: "ajax_submit_vote.php",
      data: $('#poll_form').serialize(),
      success: function( response ) {}
    });

});

然后,您应该在PHP脚本中可以访问POST变量“ poll_option”。

2020-07-26