我有一个将数据发送到控制器的ajax请求，它收集我的下拉菜单的值

错误是

POST http://localhost:65070/form/create 500 (Internal Server Error)

错误的回应是

The required anti-forgery form field "__RequestVerificationToken" is not present.

更新 我的表格

@using (Html.BeginForm())
{
    @Html.AntiForgeryToken()
    @Html.ValidationSummary(true)

    <fieldset>
        <legend>Form</legend>

        <div class="editor-label">
            @Html.LabelFor(model => model.FormName)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.FormName)
            @Html.ValidationMessageFor(model => model.FormName)
        </div>


        <div class="editor-label">
            @Html.LabelFor(model => model.MasterID, "MasterModule")
        </div>
        <div class="editor-field">
            @Html.DropDownList("MasterID", String.Empty)
            @Html.ValidationMessageFor(model => model.MasterID)
        </div>
        <select id="State" name="state"></select><br />
        <p>
            <input type="submit" value="Create" />
        </p>

    </fieldset>
}

我的ajax请求

$('#State').change(function () {
  var a = $('#State').val();
    $.ajax({
                url: "/form/create",
                type: "POST",
                data: { 'SubID': a },
                success: function (result) {
                    //        console.log(result);
                }
            });
        });

我的控制器

public ActionResult Create(Form form, int SubID)
        {
            if (ModelState.IsValid)
            {
                form.SubId =SubID;
                form.CreatedDate = DateTime.Now;
                form.CreatedBy = 1;
                form.CreatedDate = DateTime.Now;
                form.IsActive = true;
                form.ModifyBy = 1;
                form.ModifyDate = DateTime.Now;

                db.Forms.Add(form);
                db.SaveChanges();
                return RedirectToAction("Index");
            }

            ViewBag.MasterID = new SelectList(db.Departments, "MasterId", "ModuleName", form.MasterID);
            return View(form);
        }

它给500内部错误..其笨拙的帮助