如何在JavaScript或jQuery中过滤JSON数据？

一尘不染

如何在JavaScript或jQuery中过滤JSON数据？

json

如何使用Javascript或jQuery过滤JSON数据？

这是我的JSON数据：

[{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]

JavaScript：

obj1 = JSON.parse(jsondata);

现在我只想要包含网站的名称和网站数据等于 “ yahoo”

阅读 210

2020-07-27

共1个答案

一尘不染

这是您应该怎么做的方法：（适用于Google查找）

$([
  {"name":"Lenovo Thinkpad 41A4298","website":"google222"},
  {"name":"Lenovo Thinkpad 41A2222","website":"google"}
  ])
    .filter(function (i,n){
        return n.website==='google';
    });

更好的 解决方案：（Salman’s）

$.grep( [{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"}], function( n, i ) {
  return n.website==='google';
});

http://jsbin.com/yakubixi/4/edit

2020-07-27