我是android和java的新手，最近在使用baseadapter将获取的json数据显示到listview中时遇到问题。起初我使用了这段代码

  @Override
  protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

   new TheTask().execute();
  }
     class TheTask extends AsyncTask<Void,Void,String>
  {

@Override
protected String doInBackground(Void... params) {
    String str = null;
    try
    {
      HttpClient httpclient = new DefaultHttpClient();
      HttpPost httppost = new HttpPost("http://10.0.2.2/BSDI/show.php");
      HttpResponse response = httpclient.execute(httppost);
      str =  EntityUtils.toString(response.getEntity());     
    } 
    catch (IOException e) {
           // TODO Auto-generated catch block
           e.printStackTrace();
        }

    return str;

  }



@Override
    protected void onPostExecute(String result) {

    super.onPostExecute(result);

    String response = result.toString();
    try {


        ArrayList<String> stringArray = new ArrayList<String>();

        JSONArray new_array = new JSONArray(response);

        for(int i = 0, count = new_array.length(); i< count; i++)
        {
            try {
                JSONObject jsonObject = new_array.getJSONObject(i);
                stringArray.add(jsonObject.getString("title").toString());


            }
            catch (JSONException e) {
                e.printStackTrace();
            }
        }




        ArrayAdapter<String> adapter = new ArrayAdapter<String>   (MainActivity.this,R.layout.test_tuh,stringArray);            
        ListView list= (ListView) findViewById(R.id.listView1);
        list.setAdapter(adapter);

    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        //tv.setText("error2");
    }


}
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}
  }

此代码成功显示获取的json数据。但它仅显示一行。我在列表视图中需要多于一（两）行。因此，我尝试了此代码，但它不起作用，它显示了一个空白屏幕。

我的代码如下

 class TheTask extends AsyncTask<Void,Void,String>
  {

    @Override
    protected String doInBackground(Void... params) {
    String str = null;
    try
    {
      HttpClient httpclient = new DefaultHttpClient();
      HttpPost httppost = new HttpPost("http://10.0.2.2/BSDI/show.php");
      HttpResponse response = httpclient.execute(httppost);
      str =  EntityUtils.toString(response.getEntity());     
    } 
    catch (IOException e) {
           // TODO Auto-generated catch block
           e.printStackTrace();
        }

    return str;

  }


@Override
    protected void onPostExecute(String result) {


    // TODO Auto-generated method stub
    super.onPostExecute(result);

    String response = result.toString();
    try {
         arrayList=new ArrayList<get_set>();

        ArrayList<String> stringArray = new ArrayList<String>();

        JSONArray new_array = new JSONArray(response);



        for(int i = 0, count = new_array.length(); i< count; i++)
        {
            try {
                JSONObject jsonObject = new_array.getJSONObject(i);
                stringArray.add(jsonObject.getString("title").toString());


            }
            catch (JSONException e) {
                e.printStackTrace();
            }
        }



   ListView listView;
    adap= new BaseAdapter() {
        LayoutInflater inflater=(LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        @Override
        public View getView(int position, View view, ViewGroup viewgroup) {
            if (view==null) {
                view=inflater.inflate(R.layout.bsdi, null);
            }
            TextView title_tuh=(TextView) view.findViewById(R.id.title1);
            TextView notice_tuh=(TextView) view.findViewById(R.id.notice1);


            title_tuh.setText(arrayList.get(position).getTitle());
            notice_tuh=.setText(arrayList.get(position).getNotice());
            return view;
        }

        @Override
        public long getItemId(int arg0) {
            // TODO Auto-generated method stub
            return 0;
        }

        @Override
        public Object getItem(int position) {
            // TODO Auto-generated method stub
            return arrayList.get(position);
        }

        @Override
        public int getCount() {
            // TODO Auto-generated method stub
            return arrayList.size();
        }
    };


    listView=(ListView) findViewById(R.id.listView1);
    listView.setAdapter(adap);


    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        //tv.setText("error2");
    }


}

据我所知，问题就在这里

ArrayList<String> stringArray = new ArrayList<String>();

        JSONArray new_array = new JSONArray(response);



        for(int i = 0, count = new_array.length(); i< count; i++)
        {
            try {
                JSONObject jsonObject = new_array.getJSONObject(i);
                stringArray.add(jsonObject.getString("title").toString());


            }
            catch (JSONException e) {
                e.printStackTrace();
            }
        }

到目前为止，我猜测提取的json数据存储在stringArray中，但以后不使用。如果我尝试像这样使用它，则会出现错误

title_tuh.setText(stringArray .get(position).getTitle());
notice_tuh=.setText(stringArray .get(position).getNotice());

如果我尝试不使用ArrayList stringArray = new ArrayList（）;

并使用
arrayList = new ArrayList（）; 相反，这样我也会得到错误。

    arrayList=new ArrayList<get_set>();


        JSONArray new_array = new JSONArray(response);


        //JSONArray jsonArray = new JSONArray();
        for(int i = 0, count = new_array.length(); i< count; i++)
        {
            try {
                JSONObject jsonObject = new_array.getJSONObject(i);
                arrayList.add(jsonObject.getString("title").toString());
               // String in = mInflater.inflate(R.layout.custom_row_view, null);

            }
            catch (JSONException e) {
                e.printStackTrace();
            }
        }

我不知道如何解决这个问题。我看过很多在线教程，但是这些教程对我没有帮助。请帮我。