一尘不染

JSON到JavaScript数组

json

我在处理JavaScript中的JSON数据时遇到问题,特别是在将数据用作数组以及访问和迭代各个值方面。JSON文件的结构如下:

{
  "head": {
    "vars": [ "place" , "lat" , "long" , "page" ]
  } ,
  "results": {
    "bindings": [
      {
        "place": { "type": "literal" , "value": "Building A" } ,
        "lat": { "datatype": "http://www.w3.org/2001/XMLSchema#float" , "type": "typed-literal" , "value": "10.3456" } ,
        "long": { "datatype": "http://www.w3.org/2001/XMLSchema#float" , "type": "typed-literal" , "value": "-1.2345" } ,
        "page": { "type": "uri" , "value": "http://www.example.com/a.html" }
      } ,
      {
        "place": { "type": "literal" , "value": "Building B" } ,
        "lat": { "datatype": "http://www.w3.org/2001/XMLSchema#float" , "type": "typed-literal" , "value": "11.3456" } ,
        "long": { "datatype": "http://www.w3.org/2001/XMLSchema#float" , "type": "typed-literal" , "value": "-2.2345" } ,
        "page": { "type": "uri" , "value": "http://www.example.com/b.html" }
      } ,
      {
        "place": { "type": "literal" , "value": "Building C" } ,
        "lat": { "datatype": "http://www.w3.org/2001/XMLSchema#float" , "type": "typed-literal" , "value": "12.3456" } ,
        "long": { "datatype": "http://www.w3.org/2001/XMLSchema#float" , "type": "typed-literal" , "value": "-3.2345" } ,
        "page": { "type": "uri" , "value": "http://www.example.com/c.html" }
      }
    ]
  }
}

我希望能够将其转换为如下所示的JavaScript数组,以便可以迭代它并按顺序提取每个位置的值:

var locations = [
        ['Building A',10.3456,-1.2345,'http://www.example.com/a.html'],
        ['Building B',11.3456,-2.2345,'http://www.example.com/b.html'],
        ['Building C',12.3456,-3.2345,'http://www.example.com/c.html']
];

有人对如何实现这一目标有任何建议吗?我已经尝试了以下方法,但是它在JSON中选择了“类型”,而不仅仅是值:

$.each(JSONObject.results.bindings, function(i, object) {
    $.each(object, function(property, object) {
        $.each(object, function(property, value) {
              value;
        });
    });
});

任何帮助,建议,建议或更正将不胜感激。


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2020-07-27

共1个答案

一尘不染

var locations = [];
$.each(JSONObject.results.bindings, function(i, obj) {
    locations.push([obj.place.value, obj.lat.value, obj.long.value, obj.page.value]);
});

迭代通过bindings,并把该属性place.valuelat.valuelong.valuepage.value从每个元素到一个数组,再加入此数组locations

您当前的代码使用和object两次property,从而覆盖这些变量。您应该在嵌套循环中使用唯一的变量名称,以便能够区分它们。

2020-07-27