一尘不染

jqgrid如何将json格式的所有rowData发送到服务器?

json

如何将json格式的jqGrid数据发送到服务器?我是否必须使用任何外部库或脚本来实现?

谢谢!

update1 :多余的licensePlateNumber不应该在那里

[
    {
        "licensePlateNumber": ""
    },
    {
        "licensePlateNumber": "0000000000000029000721804",
        "sku": "795127",
        "description": "",
        "caseQuantity": "24",
        "isHeld": "false",
        "expirationDate": "Jul 22, 2010 12:00:00 AM"
    },
    {
        "licensePlateNumber": "0000000000000029000722323",
        "sku": "795127",
        "description": "",
        "caseQuantity": "24",
        "isHeld": "false",
        "expirationDate": "Jul 22, 2010 12:00:00 AM"
    },
    {
        "licensePlateNumber": "0000000000000029000722669",
        "sku": "795127",
        "description": "",
        "caseQuantity": "24",
        "isHeld": "false",
        "expirationDate": "Jul 22, 2010 12:00:00 AM"
    }
]

阅读 201

收藏
2020-07-27

共1个答案

一尘不染

您从另一个问题出发的方法还可以,但是jQuery.ajax在序列化数组方面遇到问题。我看到的最可靠,最标准的方法是将所有jqGrid数据序列化为JSON(例如,关于JSON.stringify函数:

$("#sendButton").click(function(){
    var gridData = jQuery("#list").getRowData();
    var postData = JSON.stringify(gridData);
    alert("JSON serialized jqGrid data:\n" + postData);
    $.ajax({
        type: "POST",
        url: "/cpsb/internalOrderList.do",
        data : {
            jgGridData: postData,
            customData: "bla bla"
        },
        dataType:"json",
        contentType: "application/json; charset=utf-8",
        success: function(response, textStatus, xhr) {
            alert("success");
        },
        error: function(xhr, textStatus, errorThrown) {
            alert("error");
        }
    });
});

参数的名称jgGridDatacustomData等等,您可以选择任何您喜欢的。

2020-07-27