我正在使用NewtonSoft JObject解析JSON字符串。如何以编程方式从动态对象获取值？我想简化代码，以免对每个对象重复说明。

public ExampleObject GetExampleObject(string jsonString)
{
ExampleObject returnObject = new ExampleObject();
dynamic dynamicResult = JObject.Parse(jsonString);
if (!ReferenceEquals(dynamicResult.album, null))
   {
       //code block to extract to another method if possible
       returnObject.Id = dynamicResult.album.id; 
       returnObject.Name = dynamicResult.album.name;
       returnObject.Description = dynamicResult.albumsdescription;
       //etc..
   }
else if(!ReferenceEquals(dynamicResult.photo, null))
   {
       //duplicated here
       returnObject.Id = dynamicResult.photo.id;
       returnObject.Name = dynamicResult.photo.name;
       returnObject.Description = dynamicResult.photo.description;
       //etc..
   }
else if..
//etc..

return returnObject;
}

有什么办法可以将“ if”语句中的代码块提取到单独的方法中，例如：

private void ExampleObject GetExampleObject([string of desired type goes here? album/photo/etc])
{
  ExampleObject returnObject = new ExampleObject();
  returnObject.Id = dynamicResult.[something goes here?].id;
  returnObject.Name = dynamicResult.[something goes here?].name;
  //etc..
  return returnObject;
}

甚至有可能因为我们不能对动态对象使用反射。还是我甚至正确使用了JObject？

谢谢。