如何从Android中的JSON对象排序JSON数组？

一尘不染

如何从Android中的JSON对象排序JSON数组？

json

我有一个JSON数组，我想根据名称和字母顺序对其进行排序。我的Json如下。

[
    {
        "UserID": 77,
        "InvID": 333,
        "Email": "sumeetssm@gmail.com",
        "Phone": "",
        "Name": "Summet",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 0,
        "InvID": 334,
        "Email": "amit@testt.com",
        "Phone": "",
        "Name": "Amit",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 3,
        "InvID": 335,
        "Email": "amitesh@yahoo.com",
        "Phone": "",
        "Name": "Amitesh",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 0,
        "InvID": 336,
        "Email": "foobar@test.com",
        "Phone": "",
        "Name": "FOO",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 0,
        "InvID": 337,
        "Email": "krazy.lance@gmail.com",
        "Phone": "",
        "Name": "Krazy",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 1,
        "InvID": 338,
        "Email": "test@yahoo.com",
        "Phone": "",
        "Name": "Test",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 0,
        "InvID": 339,
        "Email": "maktest@yahoo.com",
        "Phone": "",
        "Name": " ",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 0,
        "InvID": 340,
        "Email": "Sam@rediff.com",
        "Phone": "",
        "Name": "SAM",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 101,
        "InvID": 343,
        "Email": "anurag@yahoo.com",
        "Phone": "",
        "Name": "Anurag",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 95,
        "InvID": 379,
        "Email": "s@s.com",
        "Phone": "",
        "Name": "S",
        "Company": "",
        "Date": "2014-01-14T00:00:00"
    },
    {
        "UserID": 0,
        "InvID": 428,
        "Email": "sumeetssm@yahoo.com",
        "Phone": "",
        "Name": "Summet",
        "Company": "",
        "Date": "2014-01-16T00:00:00"
    },
    {
        "UserID": 4,
        "InvID": 494,
        "Email": "sameer@iconnectgroup.com",
        "Phone": "",
        "Name": "Sameer P",
        "Company": "",
        "Date": "2014-01-21T00:00:00"
    },
    {
        "UserID": 85,
        "InvID": 507,
        "Email": "jonny@dep.com",
        "Phone": "9404988188",
        "Name": "Jonny Dep",
        "Company": "Iconnect",
        "Date": "2014-01-22T00:00:00"
    }
]

如您所见，我有一个键值“名称”，因此我得到了尊敬的名称。我想完全基于该名称对Json数组进行排序，并且也按字母顺序排序。

阅读 411

2020-07-27

共1个答案

一尘不染

转换JSONArray为Arraylist<JSONBbject>并使用集合对您的数组列表进行排序

例如：

ArrayList<JSONObject> array = new ArrayList<JSONObject>();
JSONArray jsonArray = new JSONArray();
for (int i = 0; i < jsonArray.length(); i++) {
    try {
        array.add(jsonArray.getJSONObject(i));
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

Collections.sort(array, new Comparator<JSONObject>() {

    @Override
    public int compare(JSONObject lhs, JSONObject rhs) {
        // TODO Auto-generated method stub

        try {
            return (lhs.getString("Name").toLowerCase().compareTo(rhs.getString("Name").toLowerCase()));
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            return 0;
        }
    }
});

2020-07-27