对于一个简单的解决方案，我建议使用Jackson库，它是一个Java库，用于生成和读取带有XML扩展名的JSON，因为它只需几行简单的代码就可以将任意复杂的XML转换为JSON。

input.xml

<entries>
  <stock><name>AXL</name><time>19-07</time><price>11.34</price></stock>
  <stock><name>AIK</name><time>19-07</time><price>13.54</price></stock>
  <stock><name>ALO</name><time>19-07</time><price>16.32</price></stock>
  <stock><name>APO</name><time>19-07</time><price>13.56</price></stock>
</entries>

Java代码：

import java.io.File;
import java.util.List;

import org.codehaus.jackson.map.ObjectMapper;

import com.fasterxml.jackson.xml.XmlMapper;

public class Foo
{
  public static void main(String[] args) throws Exception
  {
    XmlMapper xmlMapper = new XmlMapper();
    List entries = xmlMapper.readValue(new File("input.xml"), List.class);

    ObjectMapper jsonMapper = new ObjectMapper();
    String json = jsonMapper.writeValueAsString(entries);
    System.out.println(json);
    // [{"name":"AXL","time":"19-07","price":"11.34"},{"name":"AIK","time":"19-07","price":"13.54"},{"name":"ALO","time":"19-07","price":"16.32"},{"name":"APO","time":"19-07","price":"13.56"}]
  }
}

该演示使用Jackson
1.7.7（较新的1.7.8也可以使用），Jackson XML
Databind 0.5.3（尚未与Jackson 1.8兼容）和Stax2
3.1.1。