在PHP中将MySQL记录集转换为JSON字符串

一尘不染

在PHP中将MySQL记录集转换为JSON字符串

json

PHP中是否可以通过MySQL记录集传递函数或类，并获得返回的JSON字符串，可以在Ajax请求中将其传递回JavaScript函数？

像这样的东西：

function recordSetToJson($recordset) {
 while($rs1 = mysql_fetch_row($recordset)) {
  for($count = 0; $count < count($rs1); $count++) {
   //  read and add field to JSON
  }
  $count++;
 }

 return $jasonstring
}

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2020-07-27

共1个答案

一尘不染

这应该工作：

function recordSetToJson($mysql_result) {
 $rs = array();
 while($rs[] = mysql_fetch_assoc($mysql_result)) {
    // you don´t really need to do anything here.
  }
 return json_encode($rs);
}

如果需要处理结果集，则可以使用以下更复杂的版本，该版本可让您添加将在每条记录上调用的回调函数，并且必须返回已处理的记录：

function recordSetToJson($mysql_result, $processing_function = null) {
 $rs = array();
 while($record = mysql_fetch_assoc($mysql_result)) {
   if(is_callable($processing_function)){
    // callback function received.  Pass the record through it.
    $processed = $processing_function($record);
    // if null was returned, skip that record from the json.
    if(!is_null($processed)) $rs[] = $processed;
   } else {
    // no callback function, use the record as is.
    $rs[] = $record;
   }
 }
 return json_encode($rs);
}

像这样使用它：

$json = recordSetToJson($results, 
    function($record){ 
      // some change you want to make to every record:
      $record["username"] = strtoupper($record["username"]);
      return $record;
    });

2020-07-27