我有一个程序,可以通过我在PyQt中编写的gui与正在使用的无线电接口。显然,无线电的主要功能之一是传输数据,但要连续进行,我必须循环写入,这会导致gui挂起。由于我从未处理过线程,因此我尝试使用QCoreApplication.processEvents().“无线电”需要在两次传输之间睡眠的方法来消除这些挂起,因此gui仍根据这些睡眠持续的时间来挂起。
QCoreApplication.processEvents()
是否有使用QThread修复此问题的简单方法?我一直在寻找有关如何使用PyQt实现多线程的教程,但是其中大多数都涉及设置服务器,并且比我需要的要先进得多。老实说,我什至不真正需要我的线程在它运行时更新任何东西,我只需要启动它,使其在后台传输,然后停止它即可。
我创建了一个小示例,展示了3种不同的简单线程处理方式。我希望它能帮助你找到解决问题的正确方法。
import sys import time from PyQt5.QtCore import (QCoreApplication, QObject, QRunnable, QThread, QThreadPool, pyqtSignal) # Subclassing QThread # http://qt-project.org/doc/latest/qthread.html class AThread(QThread): def run(self): count = 0 while count < 5: time.sleep(1) print("A Increasing") count += 1 # Subclassing QObject and using moveToThread # http://blog.qt.digia.com/blog/2007/07/05/qthreads-no-longer-abstract class SomeObject(QObject): finished = pyqtSignal() def long_running(self): count = 0 while count < 5: time.sleep(1) print("B Increasing") count += 1 self.finished.emit() # Using a QRunnable # http://qt-project.org/doc/latest/qthreadpool.html # Note that a QRunnable isn't a subclass of QObject and therefore does # not provide signals and slots. class Runnable(QRunnable): def run(self): count = 0 app = QCoreApplication.instance() while count < 5: print("C Increasing") time.sleep(1) count += 1 app.quit() def using_q_thread(): app = QCoreApplication([]) thread = AThread() thread.finished.connect(app.exit) thread.start() sys.exit(app.exec_()) def using_move_to_thread(): app = QCoreApplication([]) objThread = QThread() obj = SomeObject() obj.moveToThread(objThread) obj.finished.connect(objThread.quit) objThread.started.connect(obj.long_running) objThread.finished.connect(app.exit) objThread.start() sys.exit(app.exec_()) def using_q_runnable(): app = QCoreApplication([]) runnable = Runnable() QThreadPool.globalInstance().start(runnable) sys.exit(app.exec_()) if __name__ == "__main__": #using_q_thread() #using_move_to_thread() using_q_runnable()