一尘不染

带有Python请求的异步请求

python

我尝试了python 请求库文档中提供的示例。

使用async.map(rs),我得到了响应代码,但是我想获得所请求的每个页面的内容。例如,这不起作用:

out = async.map(rs)
print out[0].content

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2020-02-17

共1个答案

一尘不染

注意
下面的答案是不适用于请求v0.13.0 +。编写此问题后,异步功能已移至grequests。但是,你可以将其替换requestsgrequests下面的内容,它应该可以工作。

我已经留下了这个答案,以反映原始问题,即有关使用请求<v0.13.0的问题。

async.map异步执行多个任务,你必须:

  1. 为每个对象定义一个函数(你的任务)
  2. 将该功能添加为请求中的事件挂钩
  3. 调用async.map所有请求/操作的列表

例:

from requests import async
# If using requests > v0.13.0, use
# from grequests import async

urls = [
    'http://python-requests.org',
    'http://httpbin.org',
    'http://python-guide.org',
    'http://kennethreitz.com'
]

# A simple task to do to each response object
def do_something(response):
    print response.url

# A list to hold our things to do via async
async_list = []

for u in urls:
    # The "hooks = {..." part is where you define what you want to do
    # 
    # Note the lack of parentheses following do_something, this is
    # because the response will be used as the first argument automatically
    action_item = async.get(u, hooks = {'response' : do_something})

    # Add the task to our list of things to do via async
    async_list.append(action_item)

# Do our list of things to do via async
async.map(async_list)
2020-02-17