一尘不染

flutter-bloc-如何在Ui中使用FutureBuilder正确实现Bloc Architecture

flutter

我是Flutter和Bloc架构的新手,我正在尝试将Bloc用于我的登录功能。我试图在Bloc文件中调用一个函数,但是我不知道该怎么做。如果您能帮助我看看我在使用Bloc时是否还有其他问题,我也将很高兴。这是我的用户界面代码:

MaterialButton(
                      color: Colors.deepPurple,
                      minWidth: screenAwareSize(500, context),
                      onPressed: () {
                        _submitForm(authBloc, user, pass);
                      },
 void _submitForm(AuthBloc authBloc, String user, String pass) async {
    formKey.currentState.save();
    if (formKey.currentState.validate()) {
      var response = await authBloc.login(user, pass);
//when I print(response) it shows null


    }
  }

这是我的集团课:

class AuthBloc extends MainBloc {
  final Repo _repo = Repo();
  PublishSubject<Future<UserModel>> _authController = new PublishSubject<Future<UserModel>>();
  Observable<Future<UserModel>> get auth => _authController.stream;
  login(String user, String pass) async {

    Future<UserModel> item = await _repo.login(user, pass);
    _authController.sink.add(item);
  }

  dispose() {
    _authController.close();
  }
}

AuthBloc authBloc = new AuthBloc();

这是我的API类:

class API{
 Future<UserModel> login(String user, String pass) async {
    var response =
        await client.get(base_url + "login.php?user=${user}&pass=${pass}");
    return UserModel.fromJSON(json.decode(response.body));
  }}

这是我的回购类:

 class Repo {
    final API api = new API();
  login(String user, String pass) async => await api.login(user, pass);}

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2020-08-13

共1个答案

一尘不染

我将尝试首先解释BLOC组件应该做的越短越好(并且越琐碎)。

  • UI屏幕-显然向用户显示数据
  • BLOC(或ViewModel)-决定如何向用户显示数据,是否使文本加粗,是否显示错误,是否转到下一个屏幕。
  • 回购-决定向用户显示什么数据(我们是否从db中显示内容,是否从API中获取内容,是否显示红色产品?)

您还可以根据您的应用程序执行其他操作,例如:

  • 联网-执行API请求并转换对模型的响应,这只能从回购协议访问,并且该组件唯一要做的就是从回购协议(标头,正文,URL)接收数据,并以形式将数据返回回回购协议模型(您可以查看下面的代码)。
  • 数据库-对数据库执行CRUD操作,只能从仓库访问。
  • 传感器-从本地传感器读取数据,只能从回购中访问。

现在,我建议也将BLOC模式与Dependency
Injection一起使用,没有它是没有用的。使用DI,您可以模拟所有组件直到UI,并且对所有代码进行单元测试非常容易。

另外,我认为没有必要将RxDart(library)与Streams / Future(相当于RxDart
lib的dat)混合使用。首先,我建议仅使用其中之一,并根据您的代码片段,建议您更好地了解如何整体使用Rx。

因此,下面有一个关于如何使用块模式进行登录的小代码片段(也可以检查代码注释:))。

import 'package:flutter/material.dart';
import 'package:http/http.dart' as http;

class TheUIScreen extends StatefulWidget {
  @override
  _TheUIScreenState createState() => _TheUIScreenState();
}

class _TheUIScreenState extends State<TheUIScreen> {
  //TODO: for repo, block, networking, we used dependecy injection, here we have to create and init all the dependecies;

  TheAuthBlock _block;

  @override
  void initState() {
    super.initState();
    TheAuthAPI api = TheAuthAPI();
    TheAuthRepo repo =
        TheAuthRepo(theAuthAPI: api); // we could also do repo = TheAuthRepo();
    _block =
        TheAuthBlock(repo: repo); // we could also do _block = TheAuthBlock();
  }

  @override
  Widget build(BuildContext context) {
    return Container(
      child: RaisedButton(onPressed: () {
        _block.loginUser("test", "test").then((actualUser) {
          Navigator.of(context).push(MaterialPageRoute(builder: (context) {
            return TestRoute(); // or do whatever action you need, the user is logged in
          }));
        }).catchError((error) {
          //show error, something went wrong at login;
        });
      }),
    );
  }
}

class TheAuthBlock {
  final TheAuthRepo repo;

  TheAuthBlock({this.repo = const TheAuthRepo()});

  Future<UserModel> loginUser(String email, String password) {
    return repo.login(email, password).then((userModel) {
      //TODO: here we decide HOW to display the user, you might want to transfor the UserModel into a model that's used only for UI.
      //In any way, here you should do all the processing, the UI only should only display the data, not manipulate it.
    });
  }
}

class TheAuthRepo {
  final TheAuthAPI theAuthAPI;

  const TheAuthRepo(
      {this.theAuthAPI =
          const TheAuthAPI()}); // THIS would be the default constructor but it will alow us to test it using unit tests.

  Future<UserModel> login(String email, String password) {
    //TODO: here you could also check if the user is already logged in and send the current user as a response
    if (email.isNotEmpty && password.isNotEmpty) {
      return theAuthAPI.login(email, password).then((userModel) {
        //TODO: you can do extra processing here before returning the data to the block;
      });
    } else {
      return Future.error(
          "Well you can't login with empty ddata"); // TODO: you can return differetn errors for email or pwd;
    }
  }
}

class TheAuthAPI {
  final String url;

  const TheAuthAPI({this.url = "https://my.cool.api/login"});

  Future<UserModel> login(String email, String pwd) {
    // TODO: note you return a future from this method since the login will return only once (like almost all http calls)
    Map<String, String> headers = Map(); // TODO: set any headers you need here
    Map<String, String> body = {
      "email": email,
      "pwd": pwd
    }; // TODO: change the body acordingly
    return http.post("THE URL", headers: headers, body: body).then((response) {
      //TODO: parse response here and return it
      return UserModel("test",
          "test"); // this should be generated from the response not like this
    });
  }
}

class UserModel {
  final String email;

  UserModel(this.email, this.pass);

  final String pass;
}
2020-08-13