1. 模块列表
  2. 函数列表
  3. __builtin__.filter()

Python __builtin__ 模块，filter() 实例源码

我们从Python开源项目中，提取了以下24个代码示例，用于说明如何使用__builtin__.filter()。

项目：hakkuframework    作者：4shadoww    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：packaging    作者：blockstack    | 项目源码 | 文件源码 
def __and__(self, other):
        ''' Intersection is the minimum of corresponding counts.

        >>> Counter('abbb') & Counter('bcc')
        Counter({'b': 1})

        '''
        if not isinstance(other, Counter):
            return NotImplemented
        _min = min
        result = Counter()
        if len(self) < len(other):
            self, other = other, self
        for elem in filter(self.__contains__, other):
            newcount = _min(self[elem], other[elem])
            if newcount > 0:
                result[elem] = newcount
        return result
项目：packaging    作者：blockstack    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：islam-buddy    作者：hamir    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：FightstickDisplay    作者：calexil    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：cryptogram    作者：xinmingzhang    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：Repobot    作者：Desgard    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：UMOG    作者：hsab    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：beepboop    作者：nicolehe    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：hackathon    作者：vertica    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：yatta_reader    作者：sound88    | 项目源码 | 文件源码 
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/
项目：hakkuframework    作者：4shadoww    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：packaging    作者：blockstack    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：packaging    作者：blockstack    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：islam-buddy    作者：hamir    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：PyDataLondon29-EmbarrassinglyParallelDAWithAWSLambda    作者：SignalMedia    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：FightstickDisplay    作者：calexil    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：cryptogram    作者：xinmingzhang    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：Repobot    作者：Desgard    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：UMOG    作者：hsab    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：blackmamba    作者：zrzka    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：beepboop    作者：nicolehe    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：hackathon    作者：vertica    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))
项目：yatta_reader    作者：sound88    | 项目源码 | 文件源码 
def lfilter(*args, **kwargs):
        return list(filter(*args, **kwargs))