Java Armstrong号码 Java冒泡排序 Java不使用递归析因程序 Java Armstrong号码 public class Tester { public static void main(String[] args) { int c = 0, a, temp; int m = 153; int n = m; temp = n; while (n > 0) { a = n % 10; n = n / 10; c = c + (a * a * a); } if (temp == c) System.out.println(m + " is an armstrong number"); else System.out.println(m + "is not an armstrong number"); } } Java冒泡排序 Java不使用递归析因程序