Java.util.ArrayList.clone() Java.util.ArrayList.clear() Java.util.ArrayList.contains() 描述 该java.util.ArrayList.clone()返回此ArrayList实例(也就是元素本身不被复制)的浅表副本。 声明 以下是java.util.ArrayList.clone()方法的声明 public Object clone() 参数 NA 返回值 此方法返回此ArrayList实例的副本。 异常 NA 实例 以下示例显示了java.util.Arraylist.clone()方法的用法。 package com.tutorialspoint; import java.util.ArrayList; public class ArrayListDemo { public static void main(String args[]) { // create an empty array list ArrayList<StringBuilder> arrlist1 = new ArrayList<StringBuilder>(); // use add for new value arrlist1.add(new StringBuilder("Learning-")); // using clone to affect the objects pointed to by the references. ArrayList arrlist2 = (ArrayList) arrlist1.clone(); // appending the string StringBuilder strbuilder = arrlist1.get(0); strbuilder.append("list1, list2-both pointing to the same StringBuilder"); System.out.println("The 1st list prints: "); // both lists will print the same value, printing list1 for (int i = 0; i < arrlist1.size(); i++) { System.out.print(arrlist1.get(i) + " "); } System.out.println("The 2nd list prints the same i.e:"); // both lists will print the same value, printing list2 for (int i = 0; i < arrlist2.size(); i++) { System.out.print(arrlist2.get(i)); } } } 让我们编译并运行上面的程序,这将产生以下结果 The 1st list prints: Learning-list1, list2 - both pointing to the same StringBuilder The 2nd list prints the same i.e: Learning-list1, list2 - both pointing to the same StringBuilder Java.util.ArrayList.clear() Java.util.ArrayList.contains()