Java.util.Scanner.nextInt(int radix) Java.util.Scanner.nextInt() Java.util.Scanner.nextLine() 描述 所述java.util.Scanner.nextInt()方法扫描输入作为int的下一个标记。如果下一个标记无法转换为有效的int值,则此方法将抛出InputMismatchException,如下所述。如果翻译成功,扫描仪将超过匹配的输入。 声明 以下是java.util.Scanner.nextInt()方法的声明 public int nextInt(int radix) 参数 radix - 用于将标记解释为int值的基数 返回值 此方法返回从输入中扫描的int 异常 InputMismatchException - 如果下一个标记与Integer正则表达式不匹配,或者超出范围 NoSuchElementException - 如果输入已用尽 IllegalStateException - 如果此扫描程序已关闭 实例 以下示例显示了java.util.Scanner.nextInt()方法的用法。 package com.tutorialspoint; import java.util.*; public class ScannerDemo { public static void main(String[] args) { String s = "Hello World! 3 + 3.0 = 6.0 true "; // create a new scanner with the specified String Object Scanner scanner = new Scanner(s); // find the next int token and print it // loop for the whole scanner while (scanner.hasNext()) { // if the next is a int, print found and the int with radix 4 if (scanner.hasNextInt()) { System.out.println("Found :" + scanner.nextInt(4)); } // if no int is found, print "Not Found:" and the token System.out.println("Not Found :" + scanner.next()); } // close the scanner scanner.close(); } } 让我们编译并运行上面的程序,这将产生以下结果 Not Found :Hello Not Found :World! Found :3 Not Found :+ Not Found :3.0 Not Found := Not Found :6.0 Not Found :true Java.util.Scanner.nextInt() Java.util.Scanner.nextLine()